问题1000--A+B Problem

1000: A+B Problem

[命题人 : ]
时间限制 : 1.000 sec  内存限制 : 10 MB

题目描述

Calculate a+b

输入

Two integer a,b (0<=a,b<=10)

输出

Output a+b

样例输入 Copy

1 2

样例输出 Copy

3

提示

Q: Where are the input and the output? A: Your program shall always read input from stdin (Standard Input) and write output to stdout (Standard Output). For example, you can use 'scanf' in C or 'cin' in C++ to read from stdin, and use 'printf' in C or 'cout' in C++ to write to stdout. You shall not output any extra data to standard output other than that required by the problem, otherwise you will get a "Wrong Answer". User programs are not allowed to open and read from/write to files. You will get a "Runtime Error" or a "Wrong Answer" if you try to do so. Here is a sample solution for problem 1000 using C++/G++:
#include 
using namespace std;
int  main()
{
    int a,b;
    cin >> a >> b;
    cout << a+b << endl;
    return 0;
}
It's important that the return type of main() must be int when you use G++/GCC,or you may get compile error. Here is a sample solution for problem 1000 using C/GCC:
#include 

int main()
{
    int a,b;
    scanf("%d %d",&a, &b);
    printf("%d\n",a+b);
    return 0;
}
Here is a sample solution for problem 1000 using PASCAL:
program p1000(Input,Output); 
var 
  a,b:Integer; 
begin 
   Readln(a,b); 
   Writeln(a+b); 
end.
Here is a sample solution for problem 1000 using JAVA: Now java compiler is jdk 1.5, next is program for 1000
import java.io.*;
import java.util.*;
public class Main
{
            public static void main(String args[]) throws Exception
            {
                    Scanner cin=new Scanner(System.in);
                    int a=cin.nextInt(),b=cin.nextInt();
                    System.out.println(a+b);
            }
}
Old program for jdk 1.4
import java.io.*;
import java.util.*;

public class Main
{
    public static void main (String args[]) throws Exception
    {
        BufferedReader stdin = 
            new BufferedReader(
                new InputStreamReader(System.in));

        String line = stdin.readLine();
        StringTokenizer st = new StringTokenizer(line);
        int a = Integer.parseInt(st.nextToken());
        int b = Integer.parseInt(st.nextToken());
        System.out.println(a+b);
    }
}

来源/分类

POJ