问题3086--Up-up

3086: Up-up

[命题人 : ]
时间限制 : 5.000 sec  内存限制 : 64 MB

题目描述

The Up-up of a number a by a positive integer b, denoted by a↑↑b, is recursively defined by: a↑↑1 = a, a↑↑(k+1) = a (a↑↑k). Thus we have e.g. 3↑↑2 = 33 = 27, hence 3↑↑3 = 327= 7625597484987 and 3↑↑4 is roughly 103.6383346400240996*10^12. The problem is give you a pair of a and k,you must calculate a↑↑k ,the result may be large you can output the answer mod 100000000 instead.

输入

A pair of a and k .a is a positive integer and fit in __int64 and 1<=k<=200.

输出

a↑↑k mod 100000000

样例输入 Copy

3 2
3 3

样例输出 Copy

27
97484987

来源/分类